10/2x(3+4)^2=x

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Solution for 10/2x(3+4)^2=x equation: 



10/2x(3+4)^2=x

We move all terms to the left:

10/2x(3+4)^2-(x)=0



Domain of the equation: 2x(3+4)^2!=0

x∈R



We add all the numbers together, and all the variables

10/2x7^2-x=0

We add all the numbers together, and all the variables

-1x+10/2x7^2=0

We multiply all the terms by the denominator


-1x*2x7^2+10=0

Wy multiply elements

-2x^8+10=0

We do not support expression: x^8

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